\def{text AB=pari((f()=local(A,B,C1,C2,D1,D2,B1) ; A=matrix(2,2,i,j,RANDOM(7)); B=
matsupplement(matrix(2,1,i,j,RANDOM(3)+1)); C=A*[x;y];
 B1=B^(-1);A1=B1*A*B; [A,B,B1,C[1,],C[2,],B[,1],B[,2] ]);R=f();
print(R[1]","R[2]","R[3]","R[4]","R[5]","R[6]","R[7]))
}
\def{text A=item(1,\AB)}
\def{text B=item(2,\AB)}
\def{text B1=item(3,\AB)}
\def{text C1= wims(declosing item(4,\AB))}
\def{text C2= wims(declosing item(5,\AB))}
\def{text D1= wims(declosing item(6,\AB))}
\def{text D1=pari(mattranspose(\D1))}
\def{text D2= wims(declosing item(7,\AB))}
\def{text D2=pari(mattranspose(\D2))}
\def{text A1= pari(print(\B1*\A*\B))}
\def{text A2= wims(declosing \A1)}
<div class="exemple"> <span class="exemple">Exemple : </span> Soit  
\(f: \RR^2\rightarrow \RR^2) l'application linaire dfinie pour tout  \((x,y)\in \RR^2) par  \(f((x,y))= (\C1,\C2)). Soit  \(\cal B) la base canonique de  \(\RR^2) et  \(\cal B')=((\D1),(\D2)) une autre base de  \(\RR^2). Vrifier que l'on a : 
<p align="center">\(M_{\cal B}(f) )= \(\A) , 
 \(M_{\cal B'}^{\cal B}(f) )= \(\B)
<br> \(M_{\cal B}^{\cal B'}(f) )=\( \B1) , 
  \(M_{\cal B'}(f)) = \([\A1])</p>
</div>
 
	On remarquera que  la matrice associe  une application linaire 
	<span class="defn">dpend</span> du choix des bases dans les espaces 
	de dpart et d'arrive.    

 